Explain why the measured volume of the O2(g) is smaller than the calculated volume. Assume all equipment is functioning properly. Let Pint be the internal pressure of the gas. (d) The student further cools the cylinder to - 180☌ and observes that the measured volume of the O2(8) is substantially smaller than the volume that is calculated using the ideal gas law. 1.2 Irreversible and Reversible Processes Consider a gas inside a rigid cylinder fitted with a movable piston. Using principles of kinetic molecular theory, explain why the volume of the 02(8) decreases when the temperature decreases to -55☌. (c) The student tries to change the density of the O2(g) by cooling the cylinder to -55☌, which causes the volume of the gas to decrease. Will this action change the density of the gas remaining in the cylinder? Justify your answer. The temperature of the gas remains constant at 25☌. What is the new pressure of the has if the temperature is held at 25 degrees C a. Then the has is compressed to a volume of 80mL. (b) Attempting to change the density of the O2 (s), the student opens the valve on the side of the cylinder, pushes down on the piston to release some of the gas, and closes the valve again. At 25 degrees C, gas in a rigid cylinder with a movable piston has a volume of 145mL and a pressure of 125 kPa. Calculate the density of the O2(g), in g/L, under these conditions. What is the volume of this sample when it’s temperature is increased to 30 degrees Celsius while its pressure is decreased to 90 kilopascal Advertisement Answer Expert Verified 5. (a) The cylinder has a volume of 7.95 L at 25☌ and 1.00 atm. Chemistry High School answered expert verified A rigid cylinder with a movable piston contains a 2.0-liter sample of neon gas at STP. The cylinder contains 0.325 mol of 02(8). A student investigates gas behavior using a rigid cylinder with a movable piston of negligible mass, as shown in the diagram above. Thanks for watching it.Transcribed image text: Movable Piston Valve 02(8) 7. Big result is so this is the answer off this problem. When Jiro finalists, 35.1 So your final answer is 62 point one. Genuine temperature is 35.1 Calvin or you mail too right that even when one sorry 35.1, the result is so final temperature will be initial temperature, plus increase in temperature initially is printed. And guess constant having a bed eight point 31 for quite on solving it. Tend to the power three and is number of bullets that it's six. It's and are dirty, so you you can find that change in temperature well done, divided by and into our world on is 1.75 and tow. So guess is undergoing I somatic process on work done in my somatic protest. Good work has to be done at constant pressure, so your prep pressure is given constant, so it is the I somatic process. What is the volume of the gas in the cylinder at STP (1) 5.49 L (3) 55.5 L (2) 45. We have to find its final temperature, and but when six of it 1.75 into 10 to the power three. Chemistry High School answered expert verified A rigid cylinder with a movable piston contains 50.0 liters of a gas at 30.0 degree C with a pressure of 1.00 atmosphere. Open ideal gets in a Celinda having movie with Mr the initial temperature is 27 degrees Celsius. Ideal gets so here, and it's going to six.
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